Задача №7945

Доказать тождество: $\frac{x^2}{(y-x{)}^2}+\frac{y^2}{(x-y{)}^2}-\frac{2xy}{(x-y{)}^2}=1$$\frac{x^2}{(y-x{)}^2}+\frac{y^2}{(x-y{)}^2}-\frac{2xy}{(x-y{)}^2}=1$$$\frac{x^2}{(y-x{)}^2}+\frac{y^2}{(x-y{)}^2}-\frac{2xy}{(x-y{)}^2}=1$$