Задача №2364

Неравенства с логарифмом по переменному основанию

Решите неравенство: $\frac{l o g _{x + 3} ( x ^{2} - x + 30 )}{l o g _{x + 3} ( x ^{2} - x - 1 )} \geq \frac{l g ( x ^{4} - 2 x ^{3} + x ^{2} )}{l g ( x ^{2} - x - 1 )}$ $\frac{l o g _{x + 3} ( x ^{2} - x + 30 )}{l o g _{x + 3} ( x ^{2} - x - 1 )} \geq \frac{l g ( x ^{4} - 2 x ^{3} + x ^{2} )}{l g ( x ^{2} - x - 1 )}$ $\frac{lo g _{x + 3} ( x ^{2} - x + 30 )}{lo g _{x + 3} ( x ^{2} - x - 1 )} \geq \frac{l g ( x ^{4} - 2 x ^{3} + x ^{2} )}{l g ( x ^{2} - x - 1 )}$