Задача №2185

Решите неравенство: $\frac{3}{(2^{2-x^2}-1{)}^2}-\frac{4}{2^{2-x^2}-1}+1\ge 0$$\frac{3}{(2^{2-x^2}-1{)}^2}-\frac{4}{2^{2-x^2}-1}+1\ge 0$$$\frac{3}{(2^{2-x^2}-1{)}^2}-\frac{4}{2^{2-x^2}-1}+1\ge 0$$