Задача №19780

$x^2-x-12<0$$x^2-x-12<0$$$x^2-x-12<0$$

$x^2-x-12\le 0$$x^2-x-12\le 0$$$x^2-x-12\le 0$$

$x^2-x-12>0$$x^2-x-12>0$$$x^2-x-12>0$$

$x^2-x-12\ge 0$$x^2-x-12\ge 0$$$x^2-x-12\ge 0$$