Задача №15323

Решите неравенство: $1+\frac{6}{{\log }_{3}x-3}+\frac{5}{{\log }_3^{2}x-{\log }_3\left(27x^6\right)+12}\ge 0$$1+\frac{6}{{\log }_{3}x-3}+\frac{5}{{\log }_3^{2}x-{\log }_3\left(27x^6\right)+12}\ge 0$$$1+\frac{6}{{\log }_{3}x-3}+\frac{5}{{\log }_3^{2}x-{\log }_3\left(27x^6\right)+12}\ge 0$$